What is the sum from n=1 to infinity of 1/n-1/(n^2) ?

The sum from n=1 to infinity of 1/n-1/(n^2) is diverges

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sum from n=1 to infinity of 1/n-1/(n^2)

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n ^{2}}

Apply Series Limit Comparison Test:

diverges

= diverges

\int_{4}^{7} \frac{x}{x ^{2} - 2} d x

n = 3 \sum \infty \frac{n}{e ^{3 n}}

\frac{d}{d x} (- cos (x^{2}))

x \to 2 lim (6)

x \to 0 lim (\frac{sin ( x ) - x}{x})

What is the sum from n=1 to infinity of 1/n-1/(n^2) ?
The sum from n=1 to infinity of 1/n-1/(n^2) is diverges