What is the derivative of ln(x^2-6x+1) ?

The derivative of ln(x^2-6x+1) is (2x-6)/(x^2-6x+1)

What is the first derivative of ln(x^2-6x+1) ?

The first derivative of ln(x^2-6x+1) is (2x-6)/(x^2-6x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (ln (x^{2} - 6 x + 1))

\frac{2 x - 6}{x ^{2} - 6 x + 1}

Solution steps

\frac{d}{d x} (ln (x^{2} - 6 x + 1))

Apply the chain rule:

\frac{1}{x ^{2} - 6 x + 1} \frac{d}{d x} (x^{2} - 6 x + 1)

= \frac{1}{x ^{2} - 6 x + 1} \frac{d}{d x} (x^{2} - 6 x + 1)

\frac{d}{d x} (x^{2} - 6 x + 1) = 2 x - 6

= \frac{1}{x ^{2} - 6 x + 1} (2 x - 6)

Simplify

\frac{1}{x ^{2} - 6 x + 1} (2 x - 6) : \frac{2 x - 6}{x ^{2} - 6 x + 1}

= \frac{2 x - 6}{x ^{2} - 6 x + 1}

y = 4 x, y = 4 x

\int_{0}^{0.5} sin (t^{2}) d t

3 t e^{- 5 t}

\int (5 x + 4 y) d x

\int \frac{9 + x}{9 - x} d x

What is the derivative of ln(x^2-6x+1) ?
The derivative of ln(x^2-6x+1) is (2x-6)/(x^2-6x+1)
What is the first derivative of ln(x^2-6x+1) ?
The first derivative of ln(x^2-6x+1) is (2x-6)/(x^2-6x+1)