What is (\partial)/(\partial u)(4-u^2-v^2) ?

The answer to (\partial)/(\partial u)(4-u^2-v^2) is -2u

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(4-u^2-v^2)

\frac{\partial}{\partial u} (4 - u^{2} - v^{2})

- 2 u

Solution steps

\frac{\partial}{\partial u} (4 - u^{2} - v^{2})

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (4) - \frac{\partial}{\partial u} (u^{2}) - \frac{\partial}{\partial u} (v^{2})

\frac{\partial}{\partial u} (4) = 0

\frac{\partial}{\partial u} (u^{2}) = 2 u

\frac{\partial}{\partial u} (v^{2}) = 0

= 0 - 2 u - 0

Simplify

= - 2 u

\int - 2 x - 1 d x

x \to \infty lim (0 \cdot x)

\int tan (x) sec^{\frac{3}{2}} (x) d x

\frac{d}{d θ} (cos (4 θ))

n = 0 \sum \infty (- 1)^{n} (x^{n})

What is (\partial)/(\partial u)(4-u^2-v^2) ?
The answer to (\partial)/(\partial u)(4-u^2-v^2) is -2u