What is the sum from n=0 to infinity of (3/5)^{n/2} ?

The sum from n=0 to infinity of (3/5)^{n/2} is converges

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sum from n=0 to infinity of (3/5)^{n/2}

n = 0 \sum \infty (\frac{3}{5})^{\frac{n}{2}}

converges

Solution steps

n = 0 \sum \infty (\frac{3}{5})^{\frac{n}{2}}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} ((\frac{3 x - 4}{5 x + 2})^{- 5})

ln (\frac{x}{4 x ^{2} + x})

\frac{d}{d x} (\frac{1}{2} \cdot 3 x)

\int_{0}^{1} e^{- 3 x} d x

\frac{\partial}{\partial x} (\frac{1}{y} - 2 x sin (y))

What is the sum from n=0 to infinity of (3/5)^{n/2} ?
The sum from n=0 to infinity of (3/5)^{n/2} is converges