What is the solution for x(dy)/(dx)=-4y+x^3-x ?

The solution for x(dy)/(dx)=-4y+x^3-x is y=(x^3)/7-x/5+(c_{1})/(x^4)

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x(dy)/(dx)=-4y+x^3-x

x \frac{d y}{d x} = - 4 y + x^{3} - x

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

Solution steps

x \frac{d y}{d x} = - 4 y + x^{3} - x

Solve linear ODE:

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

y = \frac{x ^{3}}{7} - \frac{x}{5} + \frac{c _{1}}{x ^{4}}

\frac{d x}{d t} = 4 x (9 - x)

(3 x - 2)^{3} (x^{3} + 1)^{2}

\int x^{3} x^{2} + 12 d x

\frac{\partial}{\partial x} (x y^{2} z^{3})

4 x - x^{2}, 0, 2

What is the solution for x(dy)/(dx)=-4y+x^3-x ?
The solution for x(dy)/(dx)=-4y+x^3-x is y=(x^3)/7-x/5+(c_{1})/(x^4)