What is the limit as x approaches 0 of (1-cos(9x))/x ?

The limit as x approaches 0 of (1-cos(9x))/x is 0

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limit as x approaches 0 of (1-cos(9x))/x

x \to 0 lim (\frac{1 - cos ( 9 x )}{x})

0

Solution steps

x \to 0 lim (\frac{1 - cos ( 9 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{9 sin ( 9 x )}{1})

= x \to 0 lim (\frac{9 sin ( 9 x )}{1})

Plug in the value

x = 0

= \frac{9 sin ( 9 \cdot 0 )}{1}

Simplify

\frac{9 sin ( 9 \cdot 0 )}{1} : 0

= 0

f (x) e^{6} + ln (4)

y = \frac{27}{x ^{2} + 9}, at x = 2

\int e^{8 x + 3} d x

\int_{0}^{\frac{π}{2}} 17 sin^{2} (2 x) d x

x^{4} + 2 x, x = 1

What is the limit as x approaches 0 of (1-cos(9x))/x ?
The limit as x approaches 0 of (1-cos(9x))/x is 0