What is the derivative of f(x)=-3tan(x)-e^{-x} ?

The derivative of f(x)=-3tan(x)-e^{-x} is -3sec^2(x)+e^{-x}

What is the first derivative of f(x)=-3tan(x)-e^{-x} ?

The first derivative of f(x)=-3tan(x)-e^{-x} is -3sec^2(x)+e^{-x}

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derivative of

f (x) = - 3 tan (x) - e^{- x}

- 3 sec^{2} (x) + e^{- x}

Solution steps

\frac{d}{d x} (- 3 tan (x) - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 tan (x)) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (3 tan (x)) = 3 sec^{2} (x)

\frac{d}{d x} (e^{- x}) = - e^{- x}

= - 3 sec^{2} (x) - (- e^{- x})

Simplify

= - 3 sec^{2} (x) + e^{- x}

y^{^{''}} - 3 y^{^{'}} = (3 t + 8) sin (3 t)

\frac{d}{d x} (\frac{e ^{4 x}}{x ^{2}})

\int_{- 2}^{- 1} \frac{1}{x ^{3}} d x

\frac{f ( x ) g ( x )}{x}

\int (x + 1)^{2} (3 - x)^{8} d x

What is the derivative of f(x)=-3tan(x)-e^{-x} ?
The derivative of f(x)=-3tan(x)-e^{-x} is -3sec^2(x)+e^{-x}
What is the first derivative of f(x)=-3tan(x)-e^{-x} ?
The first derivative of f(x)=-3tan(x)-e^{-x} is -3sec^2(x)+e^{-x}