What is laplacetransform-2t^3\delta(t-4) ?

The answer to laplacetransform-2t^3\delta(t-4) is -128e^{-4s}

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laplacetransform-2t^3\delta(t-4)

laplace transform

- 2 t^{3} δ (t - 4)

- 128 e^{- 4 s}

Solution steps

L {- 2 t^{3} δ (t - 4)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 2 L {t^{3} δ (t - 4)}

L {t^{3} δ (t - 4)} : 64 e^{- 4 s}

= - 2 \cdot 64 e^{- 4 s}

Refine

- 264 e^{- 4 s} : - 128 e^{- 4 s}

= - 128 e^{- 4 s}

y^{^{''}} + 3 y^{^{'}} + y = (2 - 6 x) cos (x) - 9 sin (x)

x \to 0 lim (x^{- x})

n = 0 \sum \infty 3 (- \frac{6}{7})^{n}

g (x) = \frac{7}{4} x^{2} - 3 x + 12

\int \frac{y}{y ^{2} + 1} d y

What is laplacetransform-2t^3\delta(t-4) ?
The answer to laplacetransform-2t^3\delta(t-4) is -128e^{-4s}