What is the derivative of e^{3x^3-x} ?

The derivative of e^{3x^3-x} is e^{3x^3-x}(9x^2-1)

What is the first derivative of e^{3x^3-x} ?

The first derivative of e^{3x^3-x} is e^{3x^3-x}(9x^2-1)

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\frac{d}{d x} (e^{3 x^{3} - x})

e^{3 x^{3} - x} (9 x^{2} - 1)

Solution steps

\frac{d}{d x} (e^{3 x^{3} - x})

Apply the chain rule:

e^{3 x^{3} - x} \frac{d}{d x} (3 x^{3} - x)

= e^{3 x^{3} - x} \frac{d}{d x} (3 x^{3} - x)

\frac{d}{d x} (3 x^{3} - x) = 9 x^{2} - 1

= e^{3 x^{3} - x} (9 x^{2} - 1)

x^{4} - x^{3} + 2

\frac{d}{d x} (\frac{1}{2} x^{2} e^{- 2 x})

\frac{2 x + 9}{x}

\int \frac{y ^{3}}{( 1 - 2 y ^{4} ) ^{5}} d y

\int_{0}^{1} \frac{36}{x ^{2} - 36} d x

What is the derivative of e^{3x^3-x} ?
The derivative of e^{3x^3-x} is e^{3x^3-x}(9x^2-1)
What is the first derivative of e^{3x^3-x} ?
The first derivative of e^{3x^3-x} is e^{3x^3-x}(9x^2-1)