What is the tangent of y=2x^3-5x+1,(2,7) ?

The tangent of y=2x^3-5x+1,(2,7) is y=19x-31

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tangent of y=2x^3-5x+1,(2,7)

tangent of

y = 2 x^{3} - 5 x + 1, (2, 7)

y = 19 x - 31

Solution steps

Find the slope of

y = 2 x^{3} - 5 x + 1 : \frac{d y}{d x} = 6 x^{2} - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 19

Find the line with slope m=

19

and passing through

(2, 7) : y = 19 x - 31

y = 19 x - 31

x \to 1 lim (\frac{e ^{x} - e}{x - 1})

5 x + 4

(arctan (3 x))^{^{'}}

y = (arctan (5 x))^{2}

y = (8 x - x^{2})^{3}

What is the tangent of y=2x^3-5x+1,(2,7) ?
The tangent of y=2x^3-5x+1,(2,7) is y=19x-31