What is the derivative of 4x^{-3/8} ?

The derivative of 4x^{-3/8} is -3/(2x^{11/8)}

What is the first derivative of 4x^{-3/8} ?

The first derivative of 4x^{-3/8} is -3/(2x^{11/8)}

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\frac{d}{d x} (4 x^{- \frac{3}{8}})

- \frac{3}{2 x ^{\frac{11}{8}}}

Solution steps

\frac{d}{d x} (4 x^{- \frac{3}{8}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- \frac{3}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- \frac{3}{8} x^{- \frac{3}{8} - 1})

Simplify

4 (- \frac{3}{8} x^{- \frac{3}{8} - 1}) : - \frac{3}{2 x ^{\frac{11}{8}}}

= - \frac{3}{2 x ^{\frac{11}{8}}}

\int sin^{4} (2 x) cos^{4} (2 x) d x

f (x) = (4 x - 1) x^{\frac{9}{2}}

x \to 0 lim ((x + 2)^{3})

f (x) = \frac{x}{( 3 x - 5 ) ^{5}}

\int \frac{1}{30} x d x

What is the derivative of 4x^{-3/8} ?
The derivative of 4x^{-3/8} is -3/(2x^{11/8)}
What is the first derivative of 4x^{-3/8} ?
The first derivative of 4x^{-3/8} is -3/(2x^{11/8)}