What is the integral from-1 to 1 of 4x^3 ?

The integral from-1 to 1 of 4x^3 is 0

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integral from-1 to 1 of 4x^3

\int_{- 1}^{1} 4 x^{3} d x

0

Solution steps

\int_{- 1}^{1} 4 x^{3} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

4 x^{3} :

Odd

= 0

\int 1 + ln (x) + \frac{y}{x} d x

\int - 0.3 y d y

f (x) = \frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}}

x y^{^{'}} + y = 6 x y^{2}, y (1) = 9

f (t) = 6 t sin (π t)

What is the integral from-1 to 1 of 4x^3 ?
The integral from-1 to 1 of 4x^3 is 0