What is (\partial)/(\partial x)(x^2+3xy+y^2) ?

The answer to (\partial)/(\partial x)(x^2+3xy+y^2) is 2x+3y

Popular >

(\partial)/(\partial x)(x^2+3xy+y^2)

\frac{\partial}{\partial x} (x^{2} + 3 x y + y^{2})

2 x + 3 y

Solution steps

\frac{\partial}{\partial x} (x^{2} + 3 x y + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (3 x y) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 x y) = 3 y

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x + 3 y + 0

Simplify

= 2 x + 3 y

y^{^{''}} - 16 y^{^{'}} + 64 y = 0

\frac{d}{d x} (ln (\frac{( x + 2 ) e ^{3 x}}{x ^{2} + 1}))

\frac{d y}{d x} = (\frac{9 x}{9 x ^{2} - 1}) e^{- y}

\int - \frac{2 x}{( 1 + x ^{2} ) ^{2}} d x

\int \frac{1}{( a + x ) ^{2}} d x

What is (\partial)/(\partial x)(x^2+3xy+y^2) ?
The answer to (\partial)/(\partial x)(x^2+3xy+y^2) is 2x+3y