What is the derivative of 5cos(2x) ?

The derivative of 5cos(2x) is -10sin(2x)

What is the first derivative of 5cos(2x) ?

The first derivative of 5cos(2x) is -10sin(2x)

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\frac{d}{d x} (5 cos (2 x))

- 10 sin (2 x)

Solution steps

\frac{d}{d x} (5 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 5 (- sin (2 x) \cdot 2)

Simplify

= - 10 sin (2 x)

x \to b lim (\frac{x ^{2}}{2})

\frac{d x}{d y}, x y = 2

(1 + ln (x) + \frac{y}{x}) d x = (5 - ln (x)) d y

\frac{\partial}{\partial y} (5 x^{2} + y^{2})

\int \frac{7 x ^{6} + 8}{x ^{7} + 8 x} d x

What is the derivative of 5cos(2x) ?
The derivative of 5cos(2x) is -10sin(2x)
What is the first derivative of 5cos(2x) ?
The first derivative of 5cos(2x) is -10sin(2x)