en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2,y=2x+3

Solution

area

y = x^{2}, y = 2 x + 3

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{3} x^{2} - (2 x + 3) d x

Solve

\int_{- 1}^{3} x^{2} - (2 x + 3) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

integral from 0 to 8 of 7/3 x

\int_{0}^{8} \frac{7}{3} x d x

limit as x approaches 0 of 2/(3cos(x))

x \to 0 lim (\frac{2}{3 cos ( x )})

derivative of (2x-1^{-2})

\frac{d}{d x} ((2 x - 1)^{- 2})

limit as x approaches 0 of x/(2x+sin(x))

x \to 0 lim (\frac{x}{2 x + sin ( x )})

area y=(16)/(1+x^4),y=8x^2 area

y = \frac{16}{1 + x ^{4}}, y = 8 x^{2}

Frequently Asked Questions (FAQ)

What is area y=x^2,y=2x+3 ?
The answer to area y=x^2,y=2x+3 is 32/3