What is the derivative of 7cos(5x) ?

The derivative of 7cos(5x) is -35sin(5x)

What is the first derivative of 7cos(5x) ?

The first derivative of 7cos(5x) is -35sin(5x)

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\frac{d}{d x} (7 cos (5 x))

- 35 sin (5 x)

Solution steps

\frac{d}{d x} (7 cos (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (cos (5 x))

Apply the chain rule:

- sin (5 x) \frac{d}{d x} (5 x)

= - sin (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 7 (- sin (5 x) \cdot 5)

Simplify

= - 35 sin (5 x)

\int \frac{1}{9 - 25 x ^{2}} d x

\int \frac{1}{y} sin (\frac{x}{y}) + x d x

\frac{d}{d x} (b x e^{2 x y})

\int 1 + \frac{9 x}{4} d x

\frac{\partial}{\partial y} (ln (5 x + 4 y))

What is the derivative of 7cos(5x) ?
The derivative of 7cos(5x) is -35sin(5x)
What is the first derivative of 7cos(5x) ?
The first derivative of 7cos(5x) is -35sin(5x)