What is (\partial)/(\partial y)(3xcos(y)) ?

The answer to (\partial)/(\partial y)(3xcos(y)) is -3xsin(y)

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(\partial)/(\partial y)(3xcos(y))

\frac{\partial}{\partial y} (3 x cos (y))

- 3 x sin (y)

Solution steps

\frac{\partial}{\partial y} (3 x cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 3 x (- sin (y))

Simplify

= - 3 x sin (y)

\int sin^{3} (\frac{2}{3} x) cos^{4} (\frac{2}{3} x) d x

\frac{\partial}{\partial x} (2 ln (\frac{3 x y}{5 z}))

y = \frac{2 x}{sin ( x )}

\int 4 (x + 2) e^{2 x} d x

\frac{d}{d x} (\frac{- x e ^{- x} + e ^{- x}}{e ^{x}})

What is (\partial)/(\partial y)(3xcos(y)) ?
The answer to (\partial)/(\partial y)(3xcos(y)) is -3xsin(y)