What is the integral of (sec^2(x))/3 ?

The integral of (sec^2(x))/3 is 1/3 tan(x)+C

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integral of (sec^2(x))/3

\int \frac{sec ^{2} ( x )}{3} d x

\frac{1}{3} tan (x) + C

Solution steps

\int \frac{sec ^{2} ( x )}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= \frac{1}{3} tan (x)

Add a constant to the solution

= \frac{1}{3} tan (x) + C

\int_{0}^{1} 2^{x} d x

t + 1

\int (8 x - 3) ln (x) d x

\int_{0}^{4} 2 x + 4 d x

y = t^{3}, (- 1, - 1)

What is the integral of (sec^2(x))/3 ?
The integral of (sec^2(x))/3 is 1/3 tan(x)+C