What is the derivative of x^2-9x ?

The derivative of x^2-9x is 2x-9

What is the first derivative of x^2-9x ?

The first derivative of x^2-9x is 2x-9

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\frac{d}{d x} (x^{2} - 9 x)

2 x - 9

Solution steps

\frac{d}{d x} (x^{2} - 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9 x) = 9

= 2 x - 9

\int_{0}^{\frac{π}{2}} 3 cos^{2} (x) d x

\frac{d}{d x} (x ln (x) + (3 x^{2} - 2)^{3})

\int 2^{3 x + 4} d x

x \to 0 lim (cos (7 x))

x \to - 1 lim (3 - 2 x)