What is (\partial)/(\partial x)(-2x^2) ?

The answer to (\partial)/(\partial x)(-2x^2) is -4x

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(\partial)/(\partial x)(-2x^2)

\frac{\partial}{\partial x} (- 2 x^{2})

- 4 x

Solution steps

\frac{\partial}{\partial x} (- 2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 \cdot 2 x^{2 - 1}

Simplify

= - 4 x

1 + sin (π \cdot t)

\frac{d}{d x} (62 x)

e^{- \frac{2}{x}}

x e^{5 x}

\int \frac{e ^{x + 1}}{x + 1} d x

What is (\partial)/(\partial x)(-2x^2) ?
The answer to (\partial)/(\partial x)(-2x^2) is -4x