What is the derivative of (3x-2x^2)^3 ?

The derivative of (3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)

What is the first derivative of (3x-2x^2)^3 ?

The first derivative of (3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)

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derivative of

(3 x - 2 x^{2})^{3}

3 (3 x - 2 x^{2})^{2} (3 - 4 x)

Solution steps

\frac{d}{d x} ((3 x - 2 x^{2})^{3})

Apply the chain rule:

3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

= 3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

\frac{d}{d x} (3 x - 2 x^{2}) = 3 - 4 x

= 3 (3 x - 2 x^{2})^{2} (3 - 4 x)

x \to - 1 lim (\frac{x ^{3}}{x ^{2} - 1})

(- 3.5) (- 2.2)

x \to 9 - lim (x - 9)

y = 6 - 7 x

\int_{0}^{2} (3 x + 4) d x

What is the derivative of (3x-2x^2)^3 ?
The derivative of (3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)
What is the first derivative of (3x-2x^2)^3 ?
The first derivative of (3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)