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Popular >

yln(y)dx+xdy=0

Solution

y ln (y) d x + x d y = 0

Solution

y = e^{\frac{c _{1}}{x}}

Solution steps

y ln (y) d x + x d y = 0

Solve separable ODE:

y = e^{\frac{c _{1}}{x}}

y = e^{\frac{c _{1}}{x}}

Graph

Popular Examples

tangent of y=x^3-3x^2-9x+27,\at x=4 tangent of

y = x^{3} - 3 x^{2} - 9 x + 27, at x = 4

integral from-1 to 0 of (x^2-3)

\int_{- 1}^{0} (x^{2} - 3) d x

integral of (2x+1)/((x^2+x+1)^2)

\int \frac{2 x + 1}{( x ^{2} + x + 1 ) ^{2}} d x

(sqrt(x)+x)y^'=sqrt(y)+y

(x + x) y^{^{'}} = y + y

sum from n=1 to infinity of 2*0.2^n

n = 1 \sum \infty 2 \cdot 0. 2^{n}

Frequently Asked Questions (FAQ)

What is the solution for yln(y)dx+xdy=0 ?
The solution for yln(y)dx+xdy=0 is y=e^{(c_{1})/x}