What is the integral from 1 to 8 of x^{1/3} ?

The integral from 1 to 8 of x^{1/3} is 45/4

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integral from 1 to 8 of x^{1/3}

\int_{1}^{8} x^{\frac{1}{3}} d x

\frac{45}{4}

Decimal

11.25

Solution steps

\int_{1}^{8} x^{\frac{1}{3}} d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{8}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{45}{4}

\int_{0}^{1} \frac{15}{4 y - 1} d y

\frac{d}{d x} (x^{- l n (x)})

\int sin^{2} (2 t) cos (2 t) d t

x \to 5 lim (x 41 - x^{2})

\frac{d}{d v} (u^{2} + v^{2})

What is the integral from 1 to 8 of x^{1/3} ?
The integral from 1 to 8 of x^{1/3} is 45/4