What is the derivative of-64cos(4x) ?

The derivative of-64cos(4x) is 256sin(4x)

What is the first derivative of-64cos(4x) ?

The first derivative of-64cos(4x) is 256sin(4x)

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\frac{d}{d x} (- 64 cos (4 x))

256 sin (4 x)

Solution steps

\frac{d}{d x} (- 64 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 64 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - 64 (- sin (4 x) \cdot 4)

Simplify

= 256 sin (4 x)

\int 3 x^{\frac{3}{2}} d x

\int \frac{sin ( 2 x )}{36 + cos ^{2} ( x )} d x

0.5 q^{^{''}} + 10 q^{^{'}} + 100 q = 150

\int_{0}^{\infty} 3 e^{- x} d x

12 t

What is the derivative of-64cos(4x) ?
The derivative of-64cos(4x) is 256sin(4x)
What is the first derivative of-64cos(4x) ?
The first derivative of-64cos(4x) is 256sin(4x)