What is the derivative of (x^4/8+(x^2)/6-x/5+1/7) ?

The derivative of (x^4/8+(x^2)/6-x/5+1/7) is (x^3)/2+x/3-1/5

What is the first derivative of (x^4/8+(x^2)/6-x/5+1/7) ?

The first derivative of (x^4/8+(x^2)/6-x/5+1/7) is (x^3)/2+x/3-1/5

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\frac{d}{d x} (\frac{x ^{4}}{8} + \frac{x ^{2}}{6} - \frac{x}{5} + \frac{1}{7})

\frac{x ^{3}}{2} + \frac{x}{3} - \frac{1}{5}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{8} + \frac{x ^{2}}{6} - \frac{x}{5} + \frac{1}{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{8}) + \frac{d}{d x} (\frac{x ^{2}}{6}) - \frac{d}{d x} (\frac{x}{5}) + \frac{d}{d x} (\frac{1}{7})

\frac{d}{d x} (\frac{x ^{4}}{8}) = \frac{x ^{3}}{2}

\frac{d}{d x} (\frac{x ^{2}}{6}) = \frac{x}{3}

\frac{d}{d x} (\frac{x}{5}) = \frac{1}{5}

\frac{d}{d x} (\frac{1}{7}) = 0

= \frac{x ^{3}}{2} + \frac{x}{3} - \frac{1}{5} + 0

Simplify

= \frac{x ^{3}}{2} + \frac{x}{3} - \frac{1}{5}

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16 y^{^{''}} - 8 y^{^{'}} + y = 0

4 e^{- t} + 2

\int \frac{1}{1 + v ^{2}} d v

\int \frac{( ln ( x ) ) ^{5}}{x} d x

What is the derivative of (x^4/8+(x^2)/6-x/5+1/7) ?
The derivative of (x^4/8+(x^2)/6-x/5+1/7) is (x^3)/2+x/3-1/5
What is the first derivative of (x^4/8+(x^2)/6-x/5+1/7) ?
The first derivative of (x^4/8+(x^2)/6-x/5+1/7) is (x^3)/2+x/3-1/5