What is the derivative of 5/(t^2) ?

The derivative of 5/(t^2) is -(10)/(t^3)

What is the first derivative of 5/(t^2) ?

The first derivative of 5/(t^2) is -(10)/(t^3)

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derivative of

\frac{5}{t ^{2}}

- \frac{10}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{5}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 (- 2 t^{- 2 - 1})

Simplify

5 (- 2 t^{- 2 - 1}) : - \frac{10}{t ^{3}}

= - \frac{10}{t ^{3}}

\int \frac{3}{9 x ^{2} + 6 x + 1} d x

\int \frac{x ^{2} + x + 1}{x ^{2} + 1} d x

\frac{3000 - 10 x ^{2} + 1}{3 x ^{3}}

\frac{1}{2} sin (2 t)

\frac{d}{d x} (\frac{1 + x}{1 - x})

What is the derivative of 5/(t^2) ?
The derivative of 5/(t^2) is -(10)/(t^3)
What is the first derivative of 5/(t^2) ?
The first derivative of 5/(t^2) is -(10)/(t^3)