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Popular >

area 2x^2,2x+6,1,2

Solution

area

2 x^{2}, 2 x + 6, 1, 2

Solution

\frac{13}{3}

+1

Decimal

4.33333 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} 2 x^{2} - (2 x + 6) d x

Solve

\int_{1}^{2} 2 x^{2} - (2 x + 6) d x : \frac{13}{3}

The area is:

= \frac{13}{3}

Graph

Popular Examples

sin(2x)dx+cos(7y)dy=0

sin (2 x) d x + cos (7 y) d y = 0

expand (x^2-3x+2)(2x^3+1)expand

(x^{2} - 3 x + 2) (2 x^{3} + 1)

integral from 1 to 2 of 3/x+5/(x^2)

\int_{1}^{2} \frac{3}{x} + \frac{5}{x ^{2}} d x

limit as x approaches infinity of (log_{2}(x))^2

x \to \infty lim ((lo g_{2} (x))^{2})

(\partial)/(\partial x)(y^2-12x)

\frac{\partial}{\partial x} (y^{2} - 12 x)

Frequently Asked Questions (FAQ)

What is area 2x^2,2x+6,1,2 ?
The answer to area 2x^2,2x+6,1,2 is 13/3