What is the integral of sin(x)cos(x) ?

The integral of sin(x)cos(x) is (sin^2(x))/2+C

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integral of sin(x)cos(x)

\int sin (x) cos (x) d x

\frac{sin ^{2} ( x )}{2} + C

Solution steps

\int sin (x) cos (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (x)

= \frac{sin ^{2} ( x )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( x )}{2} + C

\int_{0}^{5} \frac{1}{x ^{\frac{14}{13}}} d x

f (x) = 3 x^{5} e^{2 x}

\frac{d}{d x} (9 x + 8)

4 x^{6} (x^{4} - 3 x)

x \to - 4 lim (\frac{x ^{2} - 8}{4 - x})

What is the integral of sin(x)cos(x) ?
The integral of sin(x)cos(x) is (sin^2(x))/2+C