What is the integral of x^6ln(3x) ?

The integral of x^6ln(3x) is 1/7 x^7ln(3x)-(x^7)/(49)+C

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integral of x^6ln(3x)

\int x^{6} ln (3 x) d x

\frac{1}{7} x^{7} ln (3 x) - \frac{x ^{7}}{49} + C

Solution steps

\int x^{6} ln (3 x) d x

Apply Integration By Parts

: \frac{1}{7} x^{7} ln (3 x) - \int \frac{x ^{6}}{7} d x

= \frac{1}{7} x^{7} ln (3 x) - \int \frac{x ^{6}}{7} d x

\int \frac{x ^{6}}{7} d x = \frac{x ^{7}}{49}

= \frac{1}{7} x^{7} ln (3 x) - \frac{x ^{7}}{49}

Add a constant to the solution

= \frac{1}{7} x^{7} ln (3 x) - \frac{x ^{7}}{49} + C

ln (22 x)

sin (2 x) cos (2 x)

x \to - \infty lim (0 \cdot (x))

y = 2 (x - 4)^{2}, (2, 8)

cos (x), \frac{1}{3} π

What is the integral of x^6ln(3x) ?
The integral of x^6ln(3x) is 1/7 x^7ln(3x)-(x^7)/(49)+C