What is the integral of 7x^3e^{-x^2} ?

The integral of 7x^3e^{-x^2} is 7/2 (-e^{-x^2}x^2-e^{-x^2})+C

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integral of 7x^3e^{-x^2}

\int 7 x^{3} e^{- x^{2}} d x

\frac{7}{2} (- e^{- x^{2}} x^{2} - e^{- x^{2}}) + C

Solution steps

\int 7 x^{3} e^{- x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int x^{3} e^{- x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u} u}{2} d u

= 7 \cdot \int \frac{e ^{u} u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \frac{1}{2} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= 7 \cdot \frac{1}{2} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= 7 \cdot \frac{1}{2} (e^{u} u - e^{u})

Substitute back

u = - x^{2}

= 7 \cdot \frac{1}{2} (e^{- x^{2}} (- x^{2}) - e^{- x^{2}})

Simplify

7 \cdot \frac{1}{2} (e^{- x^{2}} (- x^{2}) - e^{- x^{2}}) : \frac{7}{2} (- e^{- x^{2}} x^{2} - e^{- x^{2}})

= \frac{7}{2} (- e^{- x^{2}} x^{2} - e^{- x^{2}})

Add a constant to the solution

= \frac{7}{2} (- e^{- x^{2}} x^{2} - e^{- x^{2}}) + C

\frac{\partial}{\partial y} ((y - 2) (2 x + y - 5))

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 4 x - y}

\int_{0}^{1} (x^{2} - 3 x + 5) d x

f (x) = \frac{2}{3 x ^{\frac{2}{3}}}, at x = 64

\frac{\partial}{\partial x} (64 - 8 x^{2} - y^{2})

What is the integral of 7x^3e^{-x^2} ?
The integral of 7x^3e^{-x^2} is 7/2 (-e^{-x^2}x^2-e^{-x^2})+C