What is the derivative of e^{x-1}-1 ?

The derivative of e^{x-1}-1 is e^{x-1}

What is the first derivative of e^{x-1}-1 ?

The first derivative of e^{x-1}-1 is e^{x-1}

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\frac{d}{d x} (e^{x - 1} - 1)

e^{x - 1}

Solution steps

\frac{d}{d x} (e^{x - 1} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x - 1}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{x - 1}) = e^{x - 1}

\frac{d}{d x} (1) = 0

= e^{x - 1} - 0

Simplify

= e^{x - 1}

\frac{d y}{d x} = x^{8} y

f (x) = 1 (- 5 x + 3) (- 3 x + 2)

\int \frac{1}{7 + 2 x} d x

f (X) = 2 (\frac{X ^{2}}{20} - 2)^{2} + 2

\int e^{2 x} \cdot cos (x) d x

What is the derivative of e^{x-1}-1 ?
The derivative of e^{x-1}-1 is e^{x-1}
What is the first derivative of e^{x-1}-1 ?
The first derivative of e^{x-1}-1 is e^{x-1}