What is the integral of sec^2(x)-7 ?

The integral of sec^2(x)-7 is tan(x)-7x+C

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integral of sec^2(x)-7

\int sec^{2} (x) - 7 d x

tan (x) - 7 x + C

Solution steps

\int sec^{2} (x) - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x - \int 7 d x

\int sec^{2} (x) d x = tan (x)

\int 7 d x = 7 x

= tan (x) - 7 x

Add a constant to the solution

= tan (x) - 7 x + C

\frac{\partial}{\partial x} (x e^{11 x y})

x \to 0 lim (\frac{6 ^{x} - 7 ^{x}}{x})

\frac{d}{d x} (e^{- x} \cdot sin^{2} (x))

10 \cdot \frac{1}{1 + 6 s}

\frac{( x + 1 )}{x - 1}