What is the derivative of 2e^{x^2-5x} ?

The derivative of 2e^{x^2-5x} is 2e^{x^2-5x}(2x-5)

What is the first derivative of 2e^{x^2-5x} ?

The first derivative of 2e^{x^2-5x} is 2e^{x^2-5x}(2x-5)

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derivative of

2 e^{x^{2} - 5 x}

2 e^{x^{2} - 5 x} (2 x - 5)

Solution steps

\frac{d}{d x} (2 e^{x^{2} - 5 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x^{2} - 5 x})

Apply the chain rule:

e^{x^{2} - 5 x} \frac{d}{d x} (x^{2} - 5 x)

= e^{x^{2} - 5 x} \frac{d}{d x} (x^{2} - 5 x)

\frac{d}{d x} (x^{2} - 5 x) = 2 x - 5

= 2 e^{x^{2} - 5 x} (2 x - 5)

x \to - 3 lim (\frac{x ^{2} + 9}{x + 3})

\frac{d}{d x} (- \frac{1}{2} x^{- \frac{3}{2}})

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{x} sin (2 x)

y^{^{'}} + y (\frac{3}{x} + \frac{x}{2}) = 0

f (x) = \frac{1}{7 x - 4}

What is the derivative of 2e^{x^2-5x} ?
The derivative of 2e^{x^2-5x} is 2e^{x^2-5x}(2x-5)
What is the first derivative of 2e^{x^2-5x} ?
The first derivative of 2e^{x^2-5x} is 2e^{x^2-5x}(2x-5)