What is the derivative of-27cos(3x) ?

The derivative of-27cos(3x) is 81sin(3x)

What is the first derivative of-27cos(3x) ?

The first derivative of-27cos(3x) is 81sin(3x)

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\frac{d}{d x} (- 27 cos (3 x))

81 sin (3 x)

Solution steps

\frac{d}{d x} (- 27 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 27 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 27 (- sin (3 x) \cdot 3)

Simplify

= 81 sin (3 x)

\int \frac{1}{x ^{2} - 2 x + 1} d x

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\frac{d}{d x} (2 \cdot c \cdot x - x^{2})

\frac{d}{d x} (e^{- x} sin (y))

\frac{d}{d x} (e^{- 18 x})

What is the derivative of-27cos(3x) ?
The derivative of-27cos(3x) is 81sin(3x)
What is the first derivative of-27cos(3x) ?
The first derivative of-27cos(3x) is 81sin(3x)