What is the derivative of-(18/(ax)) ?

The derivative of-(18/(ax)) is (18)/(ax^2)

What is the first derivative of-(18/(ax)) ?

The first derivative of-(18/(ax)) is (18)/(ax^2)

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\frac{d}{d x} (- \frac{18}{a x})

\frac{18}{a x ^{2}}

Solution steps

\frac{d}{d x} (- \frac{18}{a x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{18}{a} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{18}{a} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{18}{a} (- 1 \cdot x^{- 1 - 1})

Simplify

- \frac{18}{a} (- 1 \cdot x^{- 1 - 1}) : \frac{18}{a x ^{2}}

= \frac{18}{a x ^{2}}

\frac{\partial}{\partial x} (4 x sin (3 x^{2} y))

\int_{- 2}^{18} \frac{1}{∣ 2 x ∣} d x

\frac{d}{d x} ((4 x^{3} + 6) (x + 8))

x \to \infty lim (7 x^{2} + 8)

x \to 0 + lim (sin (x) \cdot ln (2 x))

What is the derivative of-(18/(ax)) ?
The derivative of-(18/(ax)) is (18)/(ax^2)
What is the first derivative of-(18/(ax)) ?
The first derivative of-(18/(ax)) is (18)/(ax^2)