What is the solution for x^{''}+16pi^2x=0 ?

The solution for x^{''}+16pi^2x=0 is x=c_{1}cos(4pit)+c_{2}sin(4pit)

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x^{''}+16pi^2x=0

x^{^{''}} + 16 π^{2} x = 0

x = c_{1} cos (4 π t) + c_{2} sin (4 π t)

Solution steps

x^{''} (t) + 16 π^{2} x = 0

Solve linear ODE:

x = c_{1} cos (4 π t) + c_{2} sin (4 π t)

x = c_{1} cos (4 π t) + c_{2} sin (4 π t)

\int (2 x + 5)^{4} d x

y = \frac{4}{3 x ^{2}}

\frac{4}{( x ^{2} - 2 x ) ^{2}}

f (x) = - \frac{e ^{\frac{1}{x}}}{x ^{2}}

\int cos (3 t) sin (3 t) d t

What is the solution for x^{''}+16pi^2x=0 ?
The solution for x^{''}+16pi^2x=0 is x=c_{1}cos(4pit)+c_{2}sin(4pit)