What is the integral of (12x^2)/(sqrt(4x^3-1)) ?

The integral of (12x^2)/(sqrt(4x^3-1)) is 2sqrt(4x^3-1)+C

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integral of (12x^2)/(sqrt(4x^3-1))

\int \frac{12 x ^{2}}{4 x ^{3} - 1} d x

2 4 x^{3} - 1 + C

Solution steps

\int \frac{12 x ^{2}}{4 x ^{3} - 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int \frac{x ^{2}}{4 x ^{3} - 1} d x

Apply u-substitution

: \int \frac{1}{12 u} d u

= 12 \cdot \int \frac{1}{12 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \frac{1}{12} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 12 \cdot \frac{1}{12} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 4 x^{3} - 1

= 12 \cdot \frac{1}{12} \cdot 2 (4 x^{3} - 1)^{\frac{1}{2}}

Simplify

12 \cdot \frac{1}{12} \cdot 2 (4 x^{3} - 1)^{\frac{1}{2}} : 2 4 x^{3} - 1

= 2 4 x^{3} - 1

Add a constant to the solution

= 2 4 x^{3} - 1 + C

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What is the integral of (12x^2)/(sqrt(4x^3-1)) ?
The integral of (12x^2)/(sqrt(4x^3-1)) is 2sqrt(4x^3-1)+C