What is the limit as x approaches 0 of (1-cos(7x))/x ?

The limit as x approaches 0 of (1-cos(7x))/x is 0

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limit as x approaches 0 of (1-cos(7x))/x

x \to 0 lim (\frac{1 - cos ( 7 x )}{x})

0

Solution steps

x \to 0 lim (\frac{1 - cos ( 7 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{7 sin ( 7 x )}{1})

= x \to 0 lim (\frac{7 sin ( 7 x )}{1})

Plug in the value

x = 0

= \frac{7 sin ( 7 \cdot 0 )}{1}

Simplify

\frac{7 sin ( 7 \cdot 0 )}{1} : 0

= 0

11 (t + 1) y^{^{'}} - 9 y = 18 t

y^{^{'}} + \frac{1}{t} y = e^{- t^{2}}, y (1) = 12

\frac{d}{d x} (lo g_{2} ((5 x - 1)^{3}))

\frac{d}{d x} (\frac{x}{x + \frac{b}{x}})

x \to 3 + lim (a^{2} x - 12 a)

What is the limit as x approaches 0 of (1-cos(7x))/x ?
The limit as x approaches 0 of (1-cos(7x))/x is 0