What is (\partial ^2)/(\partial y^2)(x^2-y^2) ?

The answer to (\partial ^2)/(\partial y^2)(x^2-y^2) is -2

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(\partial ^2)/(\partial y^2)(x^2-y^2)

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - y^{2})

- 2

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - y^{2})

\frac{\partial}{\partial y} (x^{2} - y^{2}) = - 2 y

= \frac{\partial}{\partial y} (- 2 y)

\frac{\partial}{\partial y} (- 2 y) = - 2

= - 2

x \to - \infty lim (- \frac{1}{x})

\int 2 sin^{3} (\frac{x}{2}) d x

x^{2}, [0, 1]

y^{^{'}} = 6 x + y

\frac{d Q}{d t} = 1 - \frac{Q}{50}

What is (\partial ^2)/(\partial y^2)(x^2-y^2) ?
The answer to (\partial ^2)/(\partial y^2)(x^2-y^2) is -2