What is area y=x^2-9,y=-x+3,x=0,x=2 ?

The answer to area y=x^2-9,y=-x+3,x=0,x=2 is 58/3

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area y=x^2-9,y=-x+3,x=0,x=2

area

y = x^{2} - 9, y = - x + 3, x = 0, x = 2

\frac{58}{3}

Decimal Notation

19.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} - 9 - (- x + 3) d x

Solve

\int_{0}^{2} x^{2} - 9 - (- x + 3) d x : \frac{58}{3}

The area is:

= \frac{58}{3}

- 4 e^{4 x}

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\frac{d}{d x} (\frac{x ^{2} - 2}{5 x ^{3} + 6})

What is area y=x^2-9,y=-x+3,x=0,x=2 ?
The answer to area y=x^2-9,y=-x+3,x=0,x=2 is 58/3