What is the integral from 0 to 0.5 of tan(x) ?

The integral from 0 to 0.5 of tan(x) is 0.13058…

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integral from 0 to 0.5 of tan(x)

\int_{0}^{0.5} tan (x) d x

0.13058 \dots

Solution steps

\int_{0}^{0.5} tan (x) d x

Rewrite using trig identities

= \int_{0}^{0.5} \frac{sin ( x )}{cos ( x )} d x

Apply u-substitution

: \int_{1}^{0.87758 \dots} - \frac{1}{u} d u

= \int_{1}^{0.87758 \dots} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0.87758 \dots}^{1} - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{0.87758 \dots}^{1} \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - (- [ln ∣ u ∣]_{0.87758 \dots}^{1})

Simplify

= [ln ∣ u ∣]_{0.87758 \dots}^{1}

Compute the boundaries:

0.13058 \dots

= 0.13058 \dots

\int [(x + 3) (x - 4) + \frac{1}{x ^{2}}] d x

\int \frac{2 x ^{3} + x ^{2} - 6 x + 7}{x ^{2} + x - 6} d x

\int cos (y) d y

x \to 4 lim (\frac{1}{x - 3})

\frac{\partial}{\partial x} (\frac{x}{y} + \frac{1}{x} + \frac{1}{y})

What is the integral from 0 to 0.5 of tan(x) ?
The integral from 0 to 0.5 of tan(x) is 0.13058…