What is the derivative of (x^3)/(72)+6/x ?

The derivative of (x^3)/(72)+6/x is (x^2)/(24)-6/(x^2)

What is the first derivative of (x^3)/(72)+6/x ?

The first derivative of (x^3)/(72)+6/x is (x^2)/(24)-6/(x^2)

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derivative of

\frac{x ^{3}}{72} + \frac{6}{x}

\frac{x ^{2}}{24} - \frac{6}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{72} + \frac{6}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{72}) + \frac{d}{d x} (\frac{6}{x})

\frac{d}{d x} (\frac{x ^{3}}{72}) = \frac{x ^{2}}{24}

\frac{d}{d x} (\frac{6}{x}) = - \frac{6}{x ^{2}}

= \frac{x ^{2}}{24} - \frac{6}{x ^{2}}

\frac{d}{d x} ((x - sin (x))^{5})

\frac{d}{d x} ((x^{3} + 3 x^{2} + x - 1) (2 x^{2} - x + 1))

y = \frac{1}{3} - 6

co sin (o)

\frac{\partial}{\partial x} (ln (x + 6 y + 4 z))

What is the derivative of (x^3)/(72)+6/x ?
The derivative of (x^3)/(72)+6/x is (x^2)/(24)-6/(x^2)
What is the first derivative of (x^3)/(72)+6/x ?
The first derivative of (x^3)/(72)+6/x is (x^2)/(24)-6/(x^2)