What is the integral from-infinity to 0 of 1/(6-3x) ?

The integral from-infinity to 0 of 1/(6-3x) is diverges

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integral from-infinity to 0 of 1/(6-3x)

\int_{- \infty}^{0} \frac{1}{6 - 3 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{6 - 3 x} d x

Compute the indefinite integral:

\int \frac{1}{6 - 3 x} d x = - \frac{1}{3} ln ∣ 6 - 3 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{6 - 3 x} d x =

diverges

= diverges

\frac{d}{d x} (- 6 x)

\frac{d}{d x} (ln (x^{6} - 1))

\frac{d}{d x} (e^{s i n (x)} cos (x))

\int \frac{1}{tanh ( 3 x )} d x

What is the integral from-infinity to 0 of 1/(6-3x) ?
The integral from-infinity to 0 of 1/(6-3x) is diverges