What is the derivative of f(1)=2x^4-x^3+6x^2 ?

The derivative of f(1)=2x^4-x^3+6x^2 is 8x^3-3x^2+12x

What is the first derivative of f(1)=2x^4-x^3+6x^2 ?

The first derivative of f(1)=2x^4-x^3+6x^2 is 8x^3-3x^2+12x

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derivative of

f (1) = 2 x^{4} - x^{3} + 6 x^{2}

8 x^{3} - 3 x^{2} + 12 x

Solution steps

\frac{d}{d x} (2 x^{4} - x^{3} + 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 8 x^{3} - 3 x^{2} + 12 x

x \to \infty lim (3 - x)

\frac{d}{d x} ((3 x - 7)^{12})

\int \frac{x + 1}{2 x} d x

f (x) = e^{x} + ln (x)

What is the derivative of f(1)=2x^4-x^3+6x^2 ?
The derivative of f(1)=2x^4-x^3+6x^2 is 8x^3-3x^2+12x
What is the first derivative of f(1)=2x^4-x^3+6x^2 ?
The first derivative of f(1)=2x^4-x^3+6x^2 is 8x^3-3x^2+12x