What is the slope ofintercept (90,1),(980,60) ?

The slope ofintercept (90,1),(980,60) is y= 59/890 x-442/89

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slope ofintercept (90,1),(980,60)

slope intercept

(90, 1), (980, 60)

y = \frac{59}{890} x - \frac{442}{89}

Solution steps

Compute the slope

(90, 1), (980, 60) : m = \frac{59}{890}

Compute the

y

intercept:

b = - \frac{442}{89}

Construct the line equation

y = mx + b

where

m = \frac{59}{890}

and

b = - \frac{442}{89}

y = \frac{59}{890} x - \frac{442}{89}

n = 0 \sum \infty (\frac{x}{4})^{n}

\frac{d}{d x} (cos (x) - \frac{1}{6} cos (3 x))

\int_{1}^{2} \frac{5 x}{x ^{2} + 1} d x

\int \frac{( x + 2 )}{4 x - x ^{2}} d x

\frac{1}{60} w h

What is the slope ofintercept (90,1),(980,60) ?
The slope ofintercept (90,1),(980,60) is y= 59/890 x-442/89