What is the derivative of 2x^2+15 ?

The derivative of 2x^2+15 is 4x

What is the first derivative of 2x^2+15 ?

The first derivative of 2x^2+15 is 4x

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derivative of

2 x^{2} + 15

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (15)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (15) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d}{d x} (\frac{1}{- 3 + ( 3 x + 1 ) ^{2}})

y = sec (x), (\frac{π}{6}, 2 \frac{3}{3})

\frac{d y}{d x} = 1 + 8 y

tan^{8} (x)

\frac{\partial}{\partial y} (x^{3} + 2 x y + y^{2})