What is (\partial)/(\partial y)(3x^2y^2+3) ?

The answer to (\partial)/(\partial y)(3x^2y^2+3) is 6x^2y

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(\partial)/(\partial y)(3x^2y^2+3)

\frac{\partial}{\partial y} (3 x^{2} y^{2} + 3)

6 x^{2} y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y^{2} + 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y^{2}) + \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (3 x^{2} y^{2}) = 6 x^{2} y

\frac{\partial}{\partial y} (3) = 0

= 6 x^{2} y + 0

Simplify

= 6 x^{2} y

x^{2} - 4 x y + x \frac{d y}{d x} = 0

\int x^{\frac{- 5}{3}} d x

x^{^{'}} = 2 - x

y^{^{''}} + y = sin (t)

What is (\partial)/(\partial y)(3x^2y^2+3) ?
The answer to (\partial)/(\partial y)(3x^2y^2+3) is 6x^2y