What is the solution for t(dy)/(dt)-3y=(4t^5)/(sqrt(t^2+4)) ?

The solution for t(dy)/(dt)-3y=(4t^5)/(sqrt(t^2+4)) is y=4sqrt(t^2+4)t^3+c_{1}t^3

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t(dy)/(dt)-3y=(4t^5)/(sqrt(t^2+4))

t \frac{d y}{d t} - 3 y = \frac{4 t ^{5}}{t ^{2} + 4}

y = 4 t^{2} + 4 t^{3} + c_{1} t^{3}

Solution steps

t \frac{d y}{d t} - 3 y = \frac{4 t ^{5}}{t ^{2} + 4}

Solve linear ODE:

y = 4 t^{2} + 4 t^{3} + c_{1} t^{3}

y = 4 t^{2} + 4 t^{3} + c_{1} t^{3}

\int 11 sin^{3} (x co) s^{2} x d x

\int \frac{y ^{2}}{y - 1} d y

f (t) = t^{4}

\int y + 2 d y

n = 1 \sum \infty \frac{7}{n}

What is the solution for t(dy)/(dt)-3y=(4t^5)/(sqrt(t^2+4)) ?
The solution for t(dy)/(dt)-3y=(4t^5)/(sqrt(t^2+4)) is y=4sqrt(t^2+4)t^3+c_{1}t^3