What is the sum from n=1 to infinity of cos(1/n) ?

The sum from n=1 to infinity of cos(1/n) is diverges

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sum from n=1 to infinity of cos(1/n)

n = 1 \sum \infty cos (\frac{1}{n})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{1}{n})

Apply Series Divergence Test:

diverges

= diverges

x \frac{d y}{d x} + 6 y = x^{3} - x

y^{^{'}} - cos (t) y = t e^{t^{2} + s i n (t)}

\frac{d}{d x} (20 (1 - e^{- \frac{x}{2}}))

\int - 3 x^{2} + 100 d x

\frac{\partial}{\partial x} (\frac{x ^{2}}{x - 2 y})

What is the sum from n=1 to infinity of cos(1/n) ?
The sum from n=1 to infinity of cos(1/n) is diverges