What is the integral of ((x+1))/(x^2+2x+2) ?

The integral of ((x+1))/(x^2+2x+2) is 1/2 ln|x^2+2x+2|+C

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integral of ((x+1))/(x^2+2x+2)

\int \frac{( x + 1 )}{x ^{2} + 2 x + 2} d x

\frac{1}{2} ln x^{2} + 2 x + 2 + C

Solution steps

\int \frac{x + 1}{x ^{2} + 2 x + 2} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + 2 x + 2

= \frac{1}{2} ln x^{2} + 2 x + 2

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 2 x + 2 + C

\frac{d}{d x} (ln (\frac{1 + sin ( 4 x )}{cos ( 4 x )}))

\frac{d}{d x} (4 a x)

\int 4 x^{3} e^{4 x^{4}} d x

y = - \frac{5}{2} x + 3

(3, 2), (2, 3)

What is the integral of ((x+1))/(x^2+2x+2) ?
The integral of ((x+1))/(x^2+2x+2) is 1/2 ln|x^2+2x+2|+C